x^2-13-11=-7x+5

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Solution for x^2-13-11=-7x+5 equation:



x^2-13-11=-7x+5
We move all terms to the left:
x^2-13-11-(-7x+5)=0
We add all the numbers together, and all the variables
x^2-(-7x+5)-24=0
We get rid of parentheses
x^2+7x-5-24=0
We add all the numbers together, and all the variables
x^2+7x-29=0
a = 1; b = 7; c = -29;
Δ = b2-4ac
Δ = 72-4·1·(-29)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{165}}{2*1}=\frac{-7-\sqrt{165}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{165}}{2*1}=\frac{-7+\sqrt{165}}{2} $

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